Encoding Scheme & Number System Class 11 Computer Science NCERT Solution
SUMMARY
Encoding scheme maps text into the codes that facilitate communication among computers.
Textual data is encoded using ASCII, ISCII or Unicode.
Unicode scheme is a character encoding standard which can encode all the characters of almost all
languages of the world.
Computer being a digital system understands only binary numbers which are 0 and 1.
Encoded text is converted to binary form for processing by the computer.
Octal and hexadecimal number systems are used to simplify the binary coded representation as they
allow grouping of 3 or 4 bits of binary numbers each, respectively.
Q1. Write base values of binary, octal and hexadecimal number system.
Ans. Base value of binary – 2
Base value of Octal – 8
Base value of Hexadecimal – 16
Q2. Give full form of ASCII and ISCII.
Ans. Full forms are :
ASCII : American Standard Code for Information Interchange
ISCII : Indian Script Code for Information Interchange
Q3. Try the following conversions. (Number after bracket is showing the base)
(i) (514)8 = (?)10
(ii) (220)8 = (?)2
(iii) (76F)16 = (?)10
(iv) (4D9)16 = (?)10
(v) (11001010)2 = (?)10
(vi) (1010111)2 = (?)10
Ans. i) (514)
8 = (332)
10
ii) (220)8 = (10010000)2
iii) (76F)16 = (1903)10
iv) (4D9)16 = (1241)10
v) (11001010)2 = (202)10
vi) (1010111)2 = (87)10
Q4. Do the following conversions from decimal number to other number systems.
(i) (54)10 = (?)2
(ii) (120)10 = (?)2
(iii) (76)10 = (?)8
(iv) (889)10 = (?)8
(v) (789)10 = (?)16
(vi) (108)10 = (?)16
Ans. (i) (54)
10 = (110110)
2
(ii) (120)10 = (1111000)2
(iii) (76)10 = (114)8
(iv) (889)10 = (1571)8
(v) (789)10 = (315)16
(vi) (108)10 = (6C)16
Q5. Express the following octal numbers into their equivalent decimal numbers.
(i) 145
(ii) 6760
(iii) 455
(iv) 10.75
Ans. (i) (145)
8 = (101)
10
(ii) (6760)8 = (3568)10
(iii) (455)8 = (301)10
(iv) (10.75)8 = (8.953125)10
Q6. Express the following decimal numbers into hexadecimal numbers.
(i) 548
(ii) 4052
(iii) 58
(iv) 100.25
Ans. (548)
10 = (224)
16
(ii) (4052)10 = (FD4)16
(iii) (58)10 = (3A)16
(iv) (100.25)10 = (64.4)16
Q7. Express the following hexadecimal numbers into equivalent decimal numbers.
(i) 4A2
(ii) 9E1A
(iii) 6BD
(iv) 6C.34
Ans. (i) (4A2)
16 = (1186)
10
(ii) (9E1A)16 = (40474)10
(iii) (6BD)16 = (1725)10
(iv) (6C.34)16 = (108.203125)10
Q8. Convert the following binary numbers into octal and hexadecimal numbers.
(i) 1110001000
(ii) 110110101
(iii) 1010100
(iv) 1010.1001
Ans. (i) (1110001000)
2 = (1610)
8 = (388)
16
(ii) (110110101)2 = (665)8 = (1B5)16
(iii) (1010100)2 = (124)8 = (54)16
(iv) (1010.1001)2 = (12.44)8 = (A.9)16
Q9. Write binary equivalent of the following octal numbers.
(i) 2306
(ii) 5610
(iii) 742
(iv) 65.203
Ans. (i) (2306)
8 = (10011000110)
2
(ii) (5610)8 = (101110001000)2
(iii) (742)8 = (111100010)2
(iv) (65.203)8 = (110101.010000011)2
Q10. Write binary representation of the following hexadecimal numbers.
(i) 4026
(ii) BCA1
(iii) 98E
(iv) 132.45
Ans. (i) (4026)
16 = (100000000100110)
2
(ii) (BCA1)16 = (1011110010100001)2
(iii) (98E)16 = (100110001110)2
(iv) (132.45)16 = (100110010.010001012 )
Q11. How does computer understand the following text? (hint: 7 bit ASCII code).
(i) HOTS
Ans.
ASCII value of H is 72 and its equivalent 7-bit binary code = 1001000
ASCII value of O is 79 and its equivalent 7-bit binary code = 1001111
ASCII value of T is 84 and its equivalent 7-bit binary code = 1010100
ASCII value of S is 83 and its equivalent 7-bit binary code = 1010011
H O T S ASCII Code 72 79 84 83 Binary Code 1001000 1001111 1010100 1010011
Number System Class 11 Computer Science
Binary equivalent of complete word “HOTS” is given below :
HOTS = 1001000100111110101001010011
(ii) Main
Ans.
ASCII value of ‘M’ is 77 and its equivalent 7-bit binary code = 1001101
ASCII value of ‘a’ is 97 and its equivalent 7-bit binary code = 1100001
ASCII value of ‘i’ is 105 and its equivalent 7-bit binary code = 1101001
ASCII value of ‘n’ is 110 and its equivalent 7-bit binary code = 1101110
M a i n ASCII Code 77 97 105 110 Binary Code 1001101 1100001 1101001 1101110
Number System Class 11 Computer Science
Binary equivalent of complete word “Main” is given below :
Main = 1001101110000111010011101110
(iii) CaSe
Ans.
ASCII value of ‘C’ is 67 and its equivalent 7-bit binary code = 1000011
ASCII value of ‘a’ is 97 and its equivalent 7-bit binary code = 1100001
ASCII value of ‘S’ is 83 and its equivalent 7-bit binary code = 1010011
ASCII value of ‘e’ is 101 and its equivalent 7-bit binary code = 1101110
C a S e ASCII Code 67 97 83 101 Binary Code 1000011 1100001 1010011 1100101
Number System Class 11 Computer Science
Binary equivalent of complete word “CaSe” is given below :
CaSe = 1000011 110000110100111100101
Q12. The hexadecimal number system uses 16 literals(0–9, A–F). Write down its base value.
Ans. 16
Q13. Let X be a number system having B symbols only. Write down the base value of this number system.
Ans. Base value of this number system is B.
As we know the number of symbols is equal to base number like in binary there are two symbols so base value is two similarly in Octal, Decimal and Hexadecimal
Q14. Write the equivalent hexadecimal and binary values for each character of the phrase given below. ‘‘ हम सब एक”
Ans.
Symbol Hexadecimal Binary ह 0939 100100111001 म 092E 100100101110 स 0938 100100111000 ब 092C 100100101100 ए 090F 100100001111 क 0915 100100010101
Number System Class 11 Computer Science
Q15. What is the advantage of preparing a digital content in Indian language using UNICODE font?
Ans. The most important advantage of UNICODE is that we need not to add/install these fonts in our system . These are rendered automatically in the system.
Q17. Encode the word ‘COMPUTER’ using ASCII and convert the encode value into binary values.
Ans.
Symbol ASCII Binary Code C 67 1000011 O 79 1001111 M 77 1001101 P 80 1010000 U 85 1010101 T 84 1010100 E 69 1000101 R 82 1010010
Number System Class 11 Computer Science
Binary code of ‘COMPUTER’ is :
10000111001111100110110100001010101101010010001011010010
Number System Class 11 Computer Science
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